1)Factorize x^-3x-10
2)factorize 2x^+6x
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Given:
x²-3x−10
Find a pair of factors of 10 which differ by 3.
The pair 5,2 works in that 5⋅2=10 and 5−2=3
Hence we find:
x²-3x−10=(x−5)(x+2)
given 2x²+6x
2x(x+3)
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