Math, asked by ubadiblessing, 1 month ago

1)Factorize x^-3x-10
2)factorize 2x^+6x

Answers

Answered by YESHITHAK
0

Given:

x²-3x−10

Find a pair of factors of 10 which differ by 3.

The pair 5,2 works in that 5⋅2=10 and 5−2=3

Hence we find:

x²-3x−10=(x−5)(x+2)

given 2x²+6x

2x(x+3)

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