1) Factors of the given expression (x2- 4xy - 221) are....
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Answer:
∴x2−4x−21=(x−7)(x+3)
Step-by-step explanation:
Because the quadratic x
(2−4) x−21
has 1
as its coefficient of x
2
we will start with two brackets like this:
(x±a)(x±b)
what is left to be determined are the values for
a&b
to decide what these numbers are we look for two numbers that multiply to give the constant
ie.−21
but add up to the coefficient of x
ie.−4
this we do by inspection, taking note of the signs
a=1
,b=−21
sum=1−21=20
incorrect
a=−3
,b=7
sum=4
correct value but incorrect sign
a=3
b=−7
sum=−4
correct value and sign
∴x2−4x−21=(x−7)(x+3)
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