Question

1. Fig. 14.65, in A ABC, AB = AC, and XY|| BC. Prove
that BCYX is a cyclic quadrilateral.

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Answer 1

Answer:

is the diagram like this...

send the figure... otherwise unable to solve the question

Answer 2

Step-by-step explanation:

so if in ABC AB = AC now it is an isoceles triangle

now point X and Y are AB and AC as XY is parallel to BC

now let angle A be x and angle B= angle C = y

now x+ y+ y = 180

y = (180 - x )/2

now there will be one more triangle AXY

with angle A same as x

now points Xand Y will be parallel to each other

and AX =AY

now A will be same as x

so angle X= angle Y = m

so x+m +m = 180

m = (180- x)/2

so sum of angle AXY and AYX and angle YXB and angle YXC is 180

so

so m + angle YXB = 180

angle YXB = 180 - (180-x)/2

= (360 - 180 +x) / 2

= (180 + x)/2

so if it is cyclic quardilateral the sum of angle C and angle YXB should be 180 so lets check

(180-x)/2 + (180+x)/2

( 180 -x+ 180 + x) / 2

360 /2 = 180 deg

hence proved hope you like my answer if you did so then please mark me as brainliest thank uou