Question

1. Figure 10.1 shows a ray of light as it travels
from medium A to medium B. Refractive index of the
medium B relative to medium A is (NCERT EXEMPLAR)
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Answer 1

Answer:

we know

n21=1/sini

therefore

n2/n1=1/sin30

n2/n1=2

n2=2n1

therefore refractive index of medium 2 is twice that of the refractive index of medium 1

Answer 2

Explanation:

Here, ∠i = 60°, ∠r = 45°

Using Snell’s law of refraction, refractive index of medium B with respect to medium A.

sin 60/ sin 45 = $\sqrt{3} /\sqrt{2}$