1. Figure below shows the front view of two straight wires you have in equilibrium, each carrying current I in opposite direction, one into and the other out of the page. Calculate the magnitude of current I.
Attachments:
Answers
Answered by
1
Answer
Solution
the magnetic field at O due to straight wire carrying current is
B→=μ04πIa[sin30∘+sin30∘]kˆ
=μ04πIa[12+12]kˆ=μ04πIakˆ
Total magnetic field at O due to current through all the straight parallel wires carrying currents
B→=B1kˆ+B2(−kˆ)+B3(kˆ)+B4(−kˆ)+...
B=B1−B2+B3−B4+...
=μ04πIa[1−12+13−14+...]
=μ04πIaloge(1+1)=μ04πIaloge2
Here, cos30∘=ar or a=rcos30∘=r3–√/2
∴B=μ04πI(r3–√/2)loge2=μ02πIr3–√loge2
μ0I2πloge2r3–√ is the answer..
Similar questions
Math,
3 hours ago
Sociology,
3 hours ago
Math,
3 hours ago
Computer Science,
5 hours ago
Math,
7 months ago