Question

-1
Find a quadratic polynomial, the sum and product of whose zeroes are
1/4 and -1 respectively.
​

Answer 1

Answer:

x^2 -(1/4)x-1=0 is your answer

Step-by-step explanation:

• we have α+β=1/4
• and αβ= -1
• the form is x^2 -(α+β)x+αβ=0 ---------------------------- (i)
• by putting the values in equation (i) we have,
• x^2-(1/4)x-1=0
• thank u

Answer 2

Answer:

$Given, \: Sum \: of \: zeroes \: = 1/4</p><p> \\ and \: product \: of \: zeros = \: -1 \\ </p><p>Then, \: the \: quadratic \: polynomial \\ = k \: [ {x}^{2} - (sum \: of \: zeroes)x + product \: of \: zeroes ] \\ k( {x}^{2} - ( \frac{1}{4} )x - 1 \\ = k( {x}^{2} - \frac{x}{4} - 1) \\ = k( \frac{4 {x}^{2} - x - 4 }{4 } ) \\ If \: k = 4, \: then \: the \: required \: quadratic \: polynomial \: is \\⇒ \: 4 {x}^{2} - x - 4</p><p>$