1. Find a quadratic polynomial whose zeroes are reciprocals of the zeroes of the
polynomial f(x) = ax? + bx+c, a + 0,c +0.
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Let the roots of the above equation be alpha and beta. Then the roots of the new equation will be 1/alpha and 1/beta.
In the first equation...
alpha+beta=-b/a
alpha×beta=c/a
If roots of an equation are given, the equation will be
x^2-(Alpha+beta)x+ Alpha×beta
Which in this case are the reciprocals of the given equation.
So, we will find the sum and product of the reciprocal roots.
Refer the attachment..
The constant becomes the coefficient of x^2.
The coefficient of x^2 becomes the constant.
The coefficient of x remains the same.
Hope it helps...
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