Math, asked by Smrutisree, 1 year ago

1 Find a rational number between a and b
question : a = -5/6 b= -2/5
2 Find the rational number between -2 and 2
three rational number between -7/2 and -2

Answers

Answered by samikshya7
2
Hope it will help u.......plz mark as brainliest if its helpful fr uu..
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Answered by DaIncredible
4
Hey friend,
Here is the answer you were looking for:

1) A rational number between -5/6 and -2/5
Solve :
( -  \frac{5}{6}  +( -   \frac{2}{5} ) \div 2 \\  \\  = ( -  \frac{5}{6} -  \frac{2}{5}  ) \times  \frac{1}{2}  \\  \\  = ( \frac{ - 5 \times 5 - 2 \times 6}{30} ) \times  \frac{1}{2}  \\  \\  = ( \frac{ - 25 - 12}{30} ) \times  \frac{1}{2}  \\  \\  =  \frac{ - 37}{60}  \\  \\ rational \: number \: between \:  -  \frac{5}{6}  \: and \:   - \frac{ 2}{5}  \\ is \:  -  \frac{37}{60}


2) A rational number between -2 and 2
( - 2  + 2) \div 2 \\  \\ = (0) \div 2 \\  \\  =  \frac{0}{2}  \\  \\  = 0


The rational number between -2 and 2 is 0.


3) Three rational number between -7/2 and -2
( -  \frac{7}{2}  + ( - 2)) \div 2 \\  \\  = ( -  \frac{7}{2}  - 2) \times  \frac{1}{2}  \\  \\  =  \frac{ - 7 \times 1 - 2 \times 2}{4}  \\  \\  =  \frac{ - 7 - 4}{2}  \\  \\  =  \frac{ - 11}{2}  \\  \\ \: rational \: number \: between \: \\   -  \frac{7}{2}  \: and \:  -  \frac{11}{2}  \\  \\ ( -  \frac{7}{2}  + ( -  \frac{11}{2} )  \times   \frac{1}{2}  \\  \\  =  ( - \frac{7}{2}  -  \frac{11}{2}) \times  \frac{1}{2}   \\  \\  =  \frac{ - 7 - 11}{2}  \times  \frac{1}{2} \\  \\  =  \frac{ - 18}{4}   \\  \\  =  \frac{ - 9}{2} \\  \\ rational \: number \: between \:   \\ -  \frac{11}{2}   \: and \:  - 2 \\  \\  = ( -  \frac{11}{2}  + ( - 2)) \div  2 \\  \\  = ( -  \frac{11}{2}  - 2) \times  \frac{1}{2}  \\  \\  = ( \frac{ - 11 \times 1 - 2 \times 2}{2} ) \times  \frac{1}{2} \\  \\  =   \frac{ - 11 - 4}{4}  \\  \\  =  \frac{ - 15}{4}  \\  \\ so \: the \: three \: rational \: numbers \:  \\ between \:  -  \frac{7}{2}  \: and \:  - 2 \: are \:   \\ \frac{ - 11}{2} :  \frac{ - 9}{2} :  \frac{ - 15}{4}


Hope this helps!!!!

@Mahak24

Thanks.....
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