Question

1. Find c if the
system of equation,
Cx+3y + (3-c) =0, 12x+cy-C=0 has
infinitely many solution.​

Answer 1

Answer:

question says infinitely many solutions

so we know that for many solutions,

a1/a2=b1/b2=c1/c2

so putting the values we get

c/12=3/c=3-c/-c

:- c/12=3/c

> c^2 -36=0. . (cross multiplication Method)

> (c)^2-(6)^2

> (c+6)(c-6)

> c=+-6

Step-by-step explanation:

hope it helps you.

Answer 2

Value of c = ± 6 .

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