Question

1. Find k if the following pairs of circles are orthogonal() + y2 + 2by-k=0, x2 + y2 + 2ax +8=0.(1) 2 + y2 - 6x – 8y + 12=0, x+7-4x+60 +6=0 /(ii) x2 + y2 - 5x – 14y – 34 = 0, ** + y2 + 2x + 4y + k=0(iv) x2 + y2 + 4x + 8 = 0, x2 + y2 - 16y +k=0​

Answer 1

Answer:

2 + y2 - 6x – 8y + 12=0, x+7-4x+60 +6=0

Step-by-step explanation:

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