1. Find max (x+2,10) for the range 0<=x<=20 ?
2. Find min (x.x, 15) for the range 0<=x<=6 ?
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maximum of two numbers : x + 2 and 10
in the range 0 <= x <= 20
2 <= x+2 <=22 and 10 is always fixed.
if x is less than 8, then x+2 will be less than 10.
if x is more than 8, then x+2 will be more than 10.
so Max( x+2, 10) will be
= 10 for 0 <= x <= 8
= x+2 for 8 <= x <= 20
==============
is that minimum of x * x , and 15 in the range 0 <= x <= 6 ?
x² < 15 for x < √15
x² > 15 for x > √15
so minimum of x² and 15 : in the given range.
x², 0 <= x <= √15
15, √15 <= x <= 6
in the range 0 <= x <= 20
2 <= x+2 <=22 and 10 is always fixed.
if x is less than 8, then x+2 will be less than 10.
if x is more than 8, then x+2 will be more than 10.
so Max( x+2, 10) will be
= 10 for 0 <= x <= 8
= x+2 for 8 <= x <= 20
==============
is that minimum of x * x , and 15 in the range 0 <= x <= 6 ?
x² < 15 for x < √15
x² > 15 for x > √15
so minimum of x² and 15 : in the given range.
x², 0 <= x <= √15
15, √15 <= x <= 6
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