1) Find out the amount of O2 gas released when 120 gm of NaNO3 is heated. Also find the amount of NaNO2 produced.
NaNO3 -----> NaNO2 + O2
Answers
Given:
Unbalanced equation: NaNO₃ → NaNO₂ + O₂
NaNO₃ = 120gm
To find:
Find out the amount of O₂ gas released when 120 gm of NaNO₃ is heated. Also, find the amount of NaNO₂ produced.
Solution:
First balance the given equation.
2NaNO₃ → 2NaNO₂ + O₂
Na = 22.98977 g/mol
N = 14.0067 g/mol
O = 15.9994 g/mol
NaNO₃ = 22.98977 + 14.0067 + 3(15.9994) = 84.99467 g/mol
NaNO₂ = 22.98977 + 14.0067 + 2(15.9994) = 68.99527 g/mol
O₂ = 2(15.9994) = 31.9988 g/mol
2NaNO₃ → 2NaNO₂ + O₂
2×84.99467 2×68.99527 31.9988
169.98934 137.99054
169.98934 g/mol of NaNO₃ → 31.9988 g/mol of O₂
∴ 1 g/mol of NaNO₃ → 31.9988 / 169.98934 of O₂
∴ 120 gm of NaNO₃ → 31.9988 / 169.98934 × 120 of O₂
= 22.5888 gm of O₂
Therefore, 22.5888 gm O₂ gas is when 120 gm of NaNO₃ is heated.
169.98934 g/mol of NaNO₃ → 137.99054 g/mol of NaNO₂
∴ 1 g/mol of NaNO₃ → 137.99054 / 169.98934 of NaNO₂
∴ 120 gm of NaNO₃ → 137.99054 / 169.98934 × 120 of NaNO₂
= 97.4112 gm of NaNO₂
Therefore, 97.4112 gm of NaNO₂ is produced.