1) Find out the oxidation number of the oxygen in the following compounds Sodium hypochlorite Sodium chlorate Barium peroxide Oxygen fluoride Potassium superoxide.
Answers
Answered by
1
Explanation:
sodium hypo chlorite = NaClO = 0
sodium chlorate =NaClO3 = 0
barium peroxide = BaO2 = +1
oxygen fluoride = OnF2 where n= 1 ,2,3,4,5,6
then oxidation number of oxygen will be +2, +1, +2/3 ,+1/2 ,+2/5 , +1/3 respectively
potassium super oxide = KO2 = -1/2
Similar questions