Question

1) Find out the oxidation number of the oxygen in the following compounds Sodium hypochlorite Sodium chlorate Barium peroxide Oxygen fluoride Potassium superoxide.​

Answer 1

Explanation:

sodium hypo chlorite = NaClO = 0

sodium chlorate =NaClO3 = 0

barium peroxide = BaO2 = +1

oxygen fluoride = OnF2 where n= 1 ,2,3,4,5,6

then oxidation number of oxygen will be +2, +1, +2/3 ,+1/2 ,+2/5 , +1/3 respectively

potassium super oxide = KO2 = -1/2