Question

1 Find out the
the oxidation state of
element which is underlined
a) Si_br4 b) Al2_ s3 c)S0_^2- 4
d) N_o
e )HN_O2 f) Mn_ 0^2- 4
h) Te _O3
g)_S ₂ 0^-2 6​

Answer 1

Answer:

Let x be the oxidation number of O in OF

2

.

The oxidation numbers of F is −1.

Since the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0.

Therefore, x+2(−1)=0

x−2=0

x=+2

Hence, the oxidation number of O in OF

2

is +2.

Step-by-step explanation:

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