Question

1.
Find S for the G.P,
-3 /4,3/16,3/64 ..........​

Answer 1

Answer:

$\frac{3}{4} (1 + \frac{1}{4} + \frac{1}{16} + ........ \infty ) =$

$\frac{3}{4} \times \frac{1}{1 - \frac{1}{4} } = \frac{3}{4} \times \frac{4}{3} = 1$

Ans.

Step-by-step explanation:

we know that sum of infinite GP =

$\frac{a}{1 - r} .$