Question

1) Find sum and pdt of zeros: a) p(x)= 3x2-7x +15 b) p(x)=x2 -5

Answer 1

Step-by-step explanation:

(a) Given polynomial is

$p(x) = 3 {x }^{2} - 7x + 15$

Therefore,

$sum \: of \: zeroes \: = \frac{ - (coefficient \: of \: x}{coefficient \: of \: {x}^{2} }$

$= \frac{ - ( - 7)}{3}$

$= \frac{7}{3}$

$product \: of \: zeroes \: = \frac{constant \: term}{coefficient \: of \: {x}^{2} }$

$= \frac{15}{3}$

$= 5 \: ans$

(b) The given polynomial is

$p(x) = {x}^{2} - 5$

$sum \: of \: zeroes \:= \frac{ - (coefficient \: of \: x)}{coefficient \: of \: {x}^{2} }$

$\frac{ - (0)}{1}$

$= 0$

Product of zeros =

$\frac{constant \: term}{coefficient \: of \: {x}^{2} }$

$= \frac{ - 5}{1}$

$= - 5 \: \: ans$