Question

1 find tha value of
(a) 33 whole 1/3 % of 9012
(b) 25% of 10% of 1 kg

Answer 1

ANSWER



A )33 WHOLE 1/3 %OF 9012


= 100/3%.

= 33.33%

=100/3×100. × 9012

= 3004
... ....... . .....


B) 25% of 10%of 1kg

10% of 1 kg

1kg = 1000 g

= 100g


then ......................
25%of 100 g


25/100× 100

25g
..............



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Answer 2

(a) $33\dfrac{1}{3}\%$ 9012 is 3004.

(b) 25% of 10% of 1 kg is 25 g

Step-by-step explanation:

(a)

Here, $33\dfrac{1}{3}\%$ of 9012

= $\dfrac{100}{3}\%$ of 9012

• Hint. We have changed the given mixed fraction into an improper fraction.

= 9012 × $\dfrac{\dfrac{100}{3}}{100}$

• Hint. Since a% = $\dfrac{a}{100}$

= 9012 × $\dfrac{1}{3}$

= 3004

(b)

Here, 25% of 10% of 1 kg

= 25% of 10% of 1000 g

• Hint. Since 1 kg = 1000 g

= 25% of (10% of 1000 g)

= 25% of (1000 × $\dfrac{10}{100}$ g)

= 25% of 100 g

= 100 × $\dfrac{25}{100}$ g

= 25 g