Question

1. Find the 6th and nth terms of the GP 2, 6, 18,54,​

Answer 1

$we \: have \: \\ a = 2 \: \: r = \frac{6}{2} = 3 \\ \\ a_{n} = ar {}^{n}{ - }^{1} \\ = 2 \times 3^{6} - {}^{1} \\ = 2 \times 3 {}^{5} \\ = 2 \times 243 \\ = 486 \\ \\ a _{n} = ar {}^{n} { - }^{1} \\ = 2(3 {}^{n} - {}^{1} )$

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