Question

1. Find the acceleration of the body.
2.Find dispacement occuring between 5 to 15 hours.
3. Find acceleration occuring between 9 to 12 hrs.​

Answer 1

$a = \frac{dv}{dt} = slope = \frac{5}{3} km {hr}^{ - 2}$

$s = vt = area \: of \: graph = \frac{1}{2}( 9 \times 15 - 5 \times 3) = 60km$

$a = \frac{20 - 15}{12 - 9} = \frac{5}{3} km {hr}^{ - 2}$

hope it helps