Question

1. Find the amount to be paid on the principal
sum of 10000 compounded annually at the
rate of 6% pa for 2 years.
. find the ammount to be paid on the principal sum of 10000 rs. compound annually at the rate of 6%pa for 2years​

Answer 1

S O L U T I O N :

$\underline{\bf{Given\::}}$

• Principal, (P) = Rs.10000
• Rate, (R) = 6% p.a.
• Time, (n) = 2 years

$\underline{\bf{Explanation\::}}$

Using formula of the compounded annually;

$\boxed{\bf{Amount = Principal\bigg(1+\frac{R}{100} \bigg)^{n}}}$

A/q

$\mapsto\tt{Amount = 10000\bigg(1+\dfrac{6}{100} \bigg)^{2}}$

$\mapsto\tt{Amount = 10000\bigg(\dfrac{100+6}{100} \bigg)^{2}}$

$\mapsto\tt{Amount = 10000\bigg(\dfrac{106}{100} \bigg)^{2}}$

$\mapsto\tt{Amount = \cancel{10000} \times \dfrac{106}{\cancel{100} }\times\dfrac{106}{\cancel{100}} }$

$\mapsto\tt{Amount = Rs.(106 \times 106)}$

$\mapsto\bf{Amount = Rs.11236}$

Thus,

The amount to be paid will be Rs.11236 .

Answer 2

Answer:

Using formula of the compounded annually;

\boxed{\bf{Amount = Principal\bigg(1+\frac{R}{100} \bigg)^{n}}}

Amount=Principal(1+

100

R

)

n

A/q

\mapsto\tt{Amount = 10000\bigg(1+\dfrac{6}{100} \bigg)^{2}}↦Amount=10000(1+

100

6

)

2

\mapsto\tt{Amount = 10000\bigg(\dfrac{100+6}{100} \bigg)^{2}}↦Amount=10000(

100

100+6

)

2

\mapsto\tt{Amount = 10000\bigg(\dfrac{106}{100} \bigg)^{2}}↦Amount=10000(

100

106

)

2

\mapsto\tt{Amount = \cancel{10000} \times \dfrac{106}{\cancel{100} }\times\dfrac{106}{\cancel{100}} }↦Amount=

10000

×

100

106

×

100

106

\mapsto\tt{Amount = Rs.(106 \times 106)}↦Amount=Rs.(106×106)

\mapsto\bf{Amount = Rs.11236}↦Amount=Rs.11236

Thus,

The amount to be paid will be Rs.11236 .