Question

1)Find the angle between two vector a and b, where a =<-4, 3, 0> and b =<2, 0, 1>

Answer 1

The angle θ between two vectors →A and →B is related to the modulus (or magnitude) and scaler (or dot) product of →A and →B by the relationship:



→A⋅→B=|A||B|cosθ

By convention when we refer to the angle between vectors we choose the acute angle.

So for this problem, let the angle betwen →u and →v be θ then:

→u=⟨3,2⟩ and →v=⟨4,0⟩

The modulus is given by;

∣∣→u∣∣=|⟨3,2⟩|=√32+22=√9+4=√13

∣∣→v∣∣=|⟨4,0⟩|=√42+02=√16=4

And the scaler product is:

→u⋅→v=⟨3,2⟩⋅⟨4,0⟩

          =(3

hope it helps

mark as brainest

follow