Question

1. Find the angle of elevation of the top of a tower from a point on the ground, which
is 30 m away from the foot of a tower of height 10√3 m
​

Answer 1

Given the tower is 30m away from point A.

Given angle of elevation of top of tower is 30.

Let the height of tower be x

tan30=

AB

BC

=

3

1

=

30

x

x=

3

30

⋅

3

3

=

3

30×

3

=10

3

∴ Height of tower =10

3

=10×1.732

=17.32m.