Question

1. Find the angle of inclination of the straight line whose slope is
(i) 1 (ii) 3 (iii) 0

Answer 1

Let θ be the angle of inclination of the line.
Then, slope of the line, m = tan θ
(i) m = 1
tanθ = 1 = tan45°
θ = 45°
Hence angle of inclination= 45°

(ii) m = 3
tanθ = 3
θ = arctan(3)
So, angle of inclination = arctan(3)

(iii) m = 0
tanθ = 0 = tan0°
θ = 0°
Hence, angle of inclination = 0°

Answer 2

HELLO DEAR,

let the $\mathbf{\theta}$ be the angle of line,

( 1 ) . 1
m = 1

tan$\mathbf{\theta}$ = 1

tan$\mathbf{\theta}$ = tan45

$\mathbf{\theta}$ = 45

( 2 ) . 3
m = 3

tan$\mathbf{\theta}$ = 3

$\mathbf{\theta}$ = $\mathbf{tan^{-1}3}$

( 3 ) . 0
m = 0

tan$\mathbf{\theta}$ = 0

tan$\mathbf{\theta}$ = tan0

$\mathbf{\theta}$ = 0

I HOPE ITS HELP YOU DEAR,
THANKS