Question

1.
Find the angle of sector whose radius is 10 cm and area is 78.5 sq.cm
​

Answer 1

Answer:

$let \: angle \: is \: \alpha \\ given \: \: \: area \: of \: sector \: = 78.5 \\ \frac{ \alpha }{360} \times \pi \times {10}^{2} = \frac{785}{10} \\ \alpha = \frac{785 \times 360 \times 7}{22 \times 1000} = 89.92 \: degree$