Question

1. Find the angles of a parallelogram ABCD in which 3 angle A = 2 angle B.​

Answer 1

Answer:

The angles of a parallelogram ABCD in which 3 angle A = 2 angle B are

Angle A  = 72°  , Angle C = 72°

And Angle B  = Angle D = 108°

Step-by-step explanation:

In a parallelogram, there are four internal angles, and the sum of the interior angles is always 360°. A parallelogram's opposite angles are equal, and the parallelogram's consecutive angles are supplementary.

So, the parallelogram's consecutive angles are supplementary.

Supplementary angles are two angles whose measures add up to 180° .

So, angle A + angle B = 180° ------- (1)

But 3 angles A = 2 angle B (given)

Angle A = 2/3 angle B -------- (2)

Put (2) in ( 1)

2/3 angle B  + angle B = 180°

(2/3 + 1) angle B = 180°

 5/3 angle B = 180°

angle B = $=180 \times \frac{3}{5} \\= 36 \times 3\\= 108 degree$

Angle A = 2/3 angle B = 2/3 x 108  = 72°

So, Angle A  = Angle C = 72°

And Angle B  = Angle D = 108°

Answer 2

Answer:

above one is the correct