Question

1. find the area of a parallelogram whose base is 12cm and height 13cm.​

Answer 1

A N S W E R :

• Area of Parrellogram = b×h
• Area of Parrellogram = 12×13=156cm
• Area of Parrellogram = 156cm^2

Answer 2

Step-by-step explanation:

Question :-

• Find the area of parallelogram whose base is 12 cm and height is 13 cm.

To Find :-

• Area of parallelogram.

Solution :-

Given :

• Base = 12 cm
• Height = 13 cm

By using the formula,

${\longrightarrow{\sf Area\ of\ parallelogram\ =\ b \times h}}$

Where,

• b = base
• h = height

According to the question, by using the formula, we get :

${\longrightarrow{\sf Area\ of\ parallelogram\ =\ b \times h}}$

${\longrightarrow{\sf 12 \times 13}}$

${\longrightarrow{\sf 156\ cm^2}}$

$\therefore$ Hence, area of parallelogram is 156 cm².

More To Know :-

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$