Question

1. Find the area of a quadrilateral ABCD which has a diagonal 10 m and perpendiculars on it from
opposite vertices are 6 m and 5 m.​

Answer 1

$\red{\textbf{Answer :-}}$$55 \: \: {cm}^{2}$

Step-by-step explanation:

$\textsf{Length of the diagonal (AC)=10 cm}$

$\textsf{Area of quadrilateral ABCD=}$

ar(△ABC)+ar(△ACD)

$= (\LARGE\frac{1}{2} \small \times AC \times BM) + (\LARGE\frac{1}{2} \small \times AC \times DL)$

$\LARGE\frac{1}{2} \small \times AC(BM + DL)$

$\LARGE\frac{1}{2} \small \times 10(5 + 6)$

$= 5 \times 11 {cm}^{2}$

$= 55 \: \: {cm}^{2}$

$\textsf{Area of quadrilateral ABCD = }$$= 55 \: \: {cm}^{2}$

$\red{\textbf{More information :-}}$

• A quadrilateral is a polygon with four sides.

• Area: ½ x diagonal x (sum of perpendicular heights)

• Perimeter: sum of sides of the quadrilateral

• Internal angle: 90° (for square and rectangle)

Answer 2

Answer:

Area of the Quadrilateral = 55 cm ^2

Step-by-step explanation:

Hope it helps you ♥️

Mask me as Brainliest