Question

1. Find the area of a quadrilateral one of whose
diagonals is 30 cm long and the perpendiculars
from the other two vertices are 19 cm and
11 cm respectively.​

Answer 1

Step-by-step explanation:

$area \: of \: quadrilateral \: = \frac{1}{2} \times (h1 + h2) \times diagonal \\ = \frac{1}{2} \times (19 + 11) \times 30 \\ = \frac{1}{2} \times 30 \times 30 \\ = 450 {cm}^{2}$

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