Question

1. Find the area of a quadrilateral, whose one of the diagonal is 8 cm and perpendiculars from
the opposite vertices are 3 cm and 5 cm.
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Answer 1

Answer:

let the quad. be ABCD and BD be the diagonal of 8cm.

AE and CF be the perpendiculars of 3cm and 5cm respectively.

Now,

ABD forms a traingle with BD as the base and AE as Hieght.

therefore,

ar(∆ABD) = 1/2 x BD x AE = 1/2 x 8 x 3 = 12cm²

similarly, area of ∆BCD = 20cm²

since, ar(∆ABD) + ar(∆BCD) = arABCD

arABCD = (12 + 20) cm²

= 32cm².

hope it's easy for you to understand.

if there's any difficulty kindly let me know buddy.

Answer 2

Step-by-step explanation:

Hope that the attachment helps you in better understanding.