Question

1. Find the area of a rhombus having each side equal to 13 cm and one of whose diagonal
is 24cm​

Answer 1

1 decade ago
ans is 120
the other diagonal is of 10 cms.
now use formula 1/2(diagonal1*diagonal2)=120
hope it helps

Answer 2

Given that : Side = a = 13 cm and Diagonal = p = 24cm

As we know that : Area of rhombus = p.q/2

( p and q are diagonals of rhombus )

As we know that : a = √p²+q²/2 , here q = second diagonal

=> q² = 4a²-p² => q = √4a²-p²

Now, Area of rhombus :

$\frac{1}{2} p \sqrt{4 {a}^{2} - {p}^{2} } \\ \\ = > \frac{1}{2} \times 24 \times \sqrt{4 \times 13 \times 13 - 24 \times 24} \\ \\ \\ = > \frac{1}{2} \times 24 \times \sqrt{676 - 576} \\ \\ = > \frac{1}{2} \times 24 \times \sqrt{100} = \frac{1}{2} \times 24 \times 10 \\ \\ = > 120$

So, the area of rhombus will be 120 cm²

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