Question

1. Find the area of a rhombus having each side equal to 15 cm and one of whose diagonals is 24 cm
2.An equilateral triangle of side is 2a, calculate its altitude.
Those who ans these correctly I will mark it as brainlist

Answer 1

1 answer budy

Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.

AC = 24 ⇒ AO = 12

Let BO = x and AB = 15 cm (given)

By Pythagorean theorem

c2 = a2 + b2

225 = 144 + x²

x2 = 225 – 144

x2 = 81

x = 9 cm

BO = 9 cm

Diagonal BD = 2 x 9= 18cm.

Area = ½ x [ product of diagonals]

= ½ x 24 x 18

Area = 216sq.cm