Question

1-Find the area of a rhombus whose perimeter is 48 cm and altitude is 8.5 cm
2-The area of a rhombus is 139.2 cm^2 and it's altitude is 9.6 cm.Find the perimeter of the rhombus
3-Tge area of. rhombus is 184cm^2 and it's perimeter is 64 cm.Find it's altitude.
Pls explain and solve these questions....very urgent

Answer 1

Answer:

Step-by-step explanation:

1- perimeter of the rhombus=48cm

Length of each side of the given rhombus= 48/4=12cm

Area of rhombus=base *height

Base=12cm and height=8.5cm

=12*8.5

=102cm^2

Answer 2

Answer:

      Area of the given rhombus is 102 sq cm.

      Perimeter of the given rhombus is 58 cm.

      Altitude of the given rhombus is 23cm.

Explanation:

• In a rhombus all four sides are equal in length.

Solution 1 ;

• Perimeter of the rhombus = 48 cm

• Length of each side of the given rhombus = 48/4 = 12 cm

• Area of rhombus = base × height

Base = 12 cm and height = 8.5 cm

∴ Area of rhombus = 12 × 8.5

                                = 102 cm²

• So, the area of the given rhombus is 102 sq cm.

Solution 2 ;

• Given Area = 139 $cm^{2}$, height = 9.6cm

• We know that Area = base × height

139.2 = b × 9.6

b = 139.2/9.6

b = 14.5

Let b = 14.5 = side, s

• We know that perimeter = 4s

∴ perimeter = 4 × 14.5

                    = 58 cm

• So, the perimeter of the given rhombus is 58 cm.

Solution 3 ;

• Perimeter = 64 cm

       Each side = 64/4 cm = 16cm

       Base = 16cm

• Since, rhombus is a parallelogram, its area = 1/2 × base × altitude

• From given data; 1/2 × 16 × altitude = 184

∴ altitude = 184/8 = 23

• So, altitude of the given rhombus is 23cm.

To know more, go through the links;

https://brainly.in/question/6475473

https://brainly.in/question/31257882

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