Question

1. find the area of a trapezium whose parallel side are 24cm and 20cm and the distance between them is 15 cm.​

Answer 1

Step-by-step explanation:

area of trapezium is 1/2(sum of parallel sides)(height)

=1/2(24+20)X15

=1/2X44X15

=22X15

=330 cm²

Answer 2

Given:

The parallel sides of a trapezium are 24 cm and 20 cm respectively.

The distance between the parallel sides (i.e. altitude) is 15 cm

To find:

The area of the trapezium

The formula to find the area of trapezium is

$\boxed{=\frac{1}{2}\times (sum\ of\ parallel\ sides) \times altitude}\ units\ sq$

Putting the given values,

$= \frac{1}{2}\times (24+20)\times 15$

$= \frac{1}{2}\times (44)\times 15$

= 22 × 15

= 330 cm sq.

Hence,

The area of the trapezium is 330 cm sq.

Note:

Do not get confused when 'distance between two parallel sides are given.' It means the altitude or height of the trapezium.

It is perpendicular to parallel sides.