1. Find the area of a trapezium whose parallel sides are 11 m and 25 m
long, and the nonparallel sides are 15 m and 13 m long.
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Answer:
216 m2
Step-by-step explanation:
Draw DE∥BC and DL perpendicular to AB.
The opposite sides of quadrilateral DEBC are parallel.
Hence, DEBC is a parallelogram.
∴ DE = BC = 13 m
Also,
AE=(AB-EB)=(AB-DC)=(25 - 11)=14 m
For ∆DAE:
Let:
AE = a =14 m
DE = b = 13 m
DA = c =15 m
Thus, we have:
s=a+b+c2s= 14+13+152=21 m
Area of ∆DAE =s(s-a)(s-b)(s-c)
=21×(21-14)×(21-13)×(21-15)
=21×7×8×6
=7056
=84 m2
Area of ∆DAE=12×AE×DL
⇒84=12×14×DL
⇒84×214=DL
⇒DL=12 m
Area of trapezium = 12×Sum of parallel sides × Distance between them
=12×(11+25)×12
=12×36×12
=216 m2
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