Question

1. Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm, and the distance between them is 16cm with figure ​

Answer 1

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• The parallel sides of a trapezium are 28.7 cm and 22.3 cm
• The distance between the parallel sides (i.e. altitude/height) is 16 cm

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• The area of the trapezium.

The formula to find the area of a trapezium is

$\boxed{\bf{=\frac{1}{2}\times (sum\ of\ parallel\ sides) \times altitude}}\: units\ sq.$

The area of the trapezium is

$= \frac{1}{2} \times (28.7 + 22.3) \times 16$

[Sum of parallel sides, (28.7+22.3 = 51)]

And

[16 ÷ 2 = 8]

= 51 × 8

= 408 cm sq.

Hence,

The area of the trapezium is 408 cm sq.

Answer 2

Answer:

Given :-

• Parallel side of trapezoid = 28.7 cm and 22.3 cm
• Distance = 16 cm

To Find :-

Area

Solution :-

As we know that

Area = ½ (a +b) × Height

Area = ½ (28.7 + 22.3) × 16

Area = ½ × 51 × 16

Area = 1 × 51 × 8

$\huge \bf \: Area = 408 \: cm {}^{2}$

Hence :-

Area of trapezoid is 408 cm²

Learn More :-

Area of circle = πr²

Area of rectangle = length × Breadth

Volume of cuboid = Length × Breadth × Height