Math, asked by rajpriya3186, 7 months ago

1.
Find the area of a trapezium whose parallel sides are 57 cm and 33 cm and the
distance between them is 13 cm.

Answers

Answered by Anonymous
7

Answer:

Sum of Parallel sides = 57+33 = 90 cm

Height = 13 cm

Area = 1/2 x sum of parallel sides × height

Area = 1/2 x 90 × 13 ====== 45×13 = 585 sq cm

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Answered by Dynamicarmies
10

                                                                                                             

Answer : 585 cm^2

                                                                                                             

solution :

area of trapezium = \frac{1}{2}(sum of two parallelside)*height

area = \frac{1}{2} * (57 + 33)*13

area = \frac{1}{2}*90*13 = 585cm^2

                                                                                                             

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