1. Find the area
of a triangle two sides of which
are 18 cm & 10 cm & the perimeter is 42 cm.plz ans..
Answers
Answered by
3
Answer:
Area of triangle
s(s−a)(9−b)(s−0)
Here, s is the semi- perimeter,
and a,b,c are the sides of the triangle
Given a=18 cm, b=10 cm
and perimeter =42 cm
semi- perimeters=
2
perimeter
=
2
42
s=21cm.
Area of triangle
∴c=42−(18+10)cm =14 cm
∴ Area of triangle=
21.(21−18)(21−10)(21−14)
=
21.3.7.11
cm
2
=
3×7×3×7×11
cm
2
=
(3×7)
2
×11
cm
2
=21
11
cm
2
∴ Thus, the required area of the triangle is
21
11
cm
2
MARK AS BRAINLIEST
Answered by
0
Answer:
2 CM is the answer friends
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