Question

1. Find the area of a triangle whose sides are 12 cm, 6 cm and 15 cm.

Answer 1

${\large{\bf{\red{\clubs{\underline{Given :}}}}}}$

A triangle whose 3 sides are 12cm, 6cm and 15cm.

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${\large{\bf{\blue{\clubs{\underline{To Find:}}}}}}$

Find the area of triangle.

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${\large{\bf{\orange{\clubs{\underline{Solution :}}}}}}$

First,

${\blue{\bigstar{\pink{\boxed{\mathfrak{S = \frac{a + b + c}{2} }}}}}}$

Here,

${\sf{\purple{A = side \: 1}}}$

${\sf{\purple{B = Side \: 2}}}$

${\sf{\purple{C = side \: 3}}}$

Than,

${\sf{\green{S = \frac{12 + 6 + 15}{2} }}}$

${\sf{\green{S = {\cancel\frac{33}{2} }}}}$

${\bf{\red{= 16.5cm}}}$

Next,

${\blue{\bigstar{\pink{\boxed{\mathfrak{Area = \sqrt{s(s - a)(s - b)(s - c)} }}}}}}$

${\sf{\green{= \sqrt{16.5(16.5 - 12)(16.5 - 6)(16.5 - 15} )}}}$

${\sf{\green{= \sqrt{16.5 \times 4.5 \times 10.5 \times 1.5} }}}$

${\sf{\green{a= \sqrt{1169.4375} }}}$

${\blue{\underbrace{\red{\boxed{\bf{A = 34.2 {cm}^{2} }}}}}}$

So,

${\bf{The \: area \: of \: this \: triangl e \: is \: 32.2 {cm}^{2}. }}$

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${\bf{\fcolorbox{green}{red}{{{XitzNobitaxX}}}}}$

Answer 2

$\small{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Answer}}}}$

Refer to the attachment

$\huge\blue{@XxBornToShinexX}$