Question

1. Find the area of a triangle whose sides are 12 cm, 6 cm and 15 cm.

Answer 1

Answer:

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Answer 2

The triangle whose sides are

• a = 9 cm,
• b = 12 cm
• c = 15

s=a+b+c/2

s=9+12+15/2

s=18

$area = \sqrt{s(s - a)(s - b)(s - c)}$

area=

$\sqrt{18(18 - 9)(18 - 12)(18 - 15)}$

$\sqrt{18 \times 9 \times 6 \times 3}$

$\sqrt{2916}$

54 cm^2