Question

1. Find the area of a triangle whose sides are 7 cm, 9 cm and 8 cm. ​

Answer 1

• As per the data given in the question, we have to find the value of the expression.

               Given data:- Sides of the triangle is  $7cm,\ 9cm,\ 8cm.$

               To find:- Area of a triangle.

               Solution:-

• The area of a triangle is the region enclosed between the sides of the triangle.

        Let's  

       The Triangle be 'ABC'.  

        Then, AB → a, BC → b, CA → c  

        From the given information

            $\begin{array}{l}A B \rightarrow a=7 \mathrm{~cm} \\ B C \rightarrow b=9 \mathrm{~cm} \\ C A \rightarrow C=8 \mathrm{~cm}\end{array}$

       By Using "Heron's Formula".

        $\begin{array}{l}\text { Area of Triangle }=\sqrt{s(s-a)(s-b)(s-c)} \\\\ \end{array}$

                          $s=\frac{a+b+c}{2}\\s=\frac{7+9+8}{2}\\s=12cm.$

        Now,

           $\begin{array}{l}\sqrt{12(12-7)(12-9)(12-8)} \\\rightarrow \sqrt{12(5)(3)(4)}\\\begin{array}{l}\rightarrow \sqrt{12 \times} 60} \\\rightarrow \sqrt{720} \\\rightarrow 26.832\end{array}\end{array}$

     Hence we will get  are of a triangle is $26.832cm^{2} .$

Answer 2

Answer:

The area of triangle is $26.832 cm^{2}$

Step-by-step explanation:

Given data:- Sides of the triangle is $7 cm, 9 cm, 8 cm$

To find- Area of triangle

Solution -

     Area of triangle =$\sqrt{s(s-a)(s-b)(s-c)}$

$a= 7 cm\\b=9cm\\c= 8cm$

Area of triangle = $\sqrt{s(s-7)(s-9)(s-8)}$

$s = \frac{a+b+c}{2} \\s= \frac{7+9+8}{2} \\s= \frac{24}{2} \\s = 12cm$

Area of triangle= $\sqrt{12(12-7)(12-9)(12-8)}$

Area of triangle=$\sqrt{12(5)(3)(4)}$

Area of triangle=$\sqrt{720}$

Area of triangle= $26.832 cm^{2}$

The area of triangle is $26.832 cm^{2}$