Question

1. Find the area of a triangle whose sides are in the ratio 2:5:6 and its perimeter
is 520 m.​

Answer 1

Answer:

Step-by-step explanation:

2x + 5x + 6x = 520

13x = 520

x = 520/13 = 40

Therefore, sides are 80 m, 200 m and 240 m

s = (a + b + c)/2 = (80 + 200 + 240)/2 = 520/2 = 260 m

Area =

$\sqrt{s(s - a)(s - b)(s - c)} \\\sqrt{260(260 - 80)(260 - 200)(260 - 240)} \\\sqrt{260*180*60*20}\\\sqrt{10*10*10*10*13*2*2*3*3*3*2*2}\\10*10*2*2*3*\sqrt{13*3} = 1200\sqrt{39} m^{2}$

Hope this helps!

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