Question

1) Find the area of a triangle whose sides are in the ratio 9:40:41 and perimeter is 180 cm.

Answer 1

Answer:

Step-by-step explanation:

Let the sides of a triangle be 9x ,40x and 41x respectively .

according to question-

9 x + 40 x + 41 x =180 cm

=>90x =180 cm

=>x =2 cm

AB= 9x = 9*2 =18

BC=40x = 40*2 = 80

AC = 41 x = 41*2 =82

s = 18 + 80 + 82 by 2

s = 180/2 = 90

area of triangle = s(s-a)(s-b)(s-c)under root

=90(90-18)(90-80)(90-82)underroot

=90*72*10*8underroot

we can write it as

=10*9*8*9*10*8 underroot

to remove the root write one number for a pair of same number

=10*8*9

=720 ans