Question

1)Find the area of a triangle whose two sides are 18 cm and 10 cm and the perimeter is 42cm.​

Answer 1

Answer:

Step-by-step explanation:

Two sides of the triangle = 18cm and 10cm

Perimeter of the triangle = 42cm

Third side of triangle = 42 - (18+10) cm = 14cm

Semi perimeter of triangle = 42/2 = 21cm

Using heron's formula,

Area of the triangle = √s (s-a) (s-b) (s-c)

                                      = √21(21 - 18) (21 - 10) (21 - 14) cm2

                                      = √21 × 3 × 11 × 7 m2

                                      = 21√11 cm2

Answer 2

Answer:

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Step-by-step explanation:

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