Question

1. Find the area of of a triangle; whose sides
are :
(i) 10 cm, 24 cm and 26 cm​

Answer 1

Answer:  Area of triangle with a,b,c as sides and s=2a+b+c​ is s(s−a)(s−b)(s−c)

​ .

For triangle with sides 10 cm, 24 cm and 26 cm, s=210+24+26​=30

Area of the triangle with sides 10 cm, 24 cm and 26 cm =30(30−10)(30−24)(30−26)

​

=30×20×6×4

​

=6×5×4×5×6×4

​

=6×5×4

=120cm2

Step-by-step explanation:

hope you like it.

Answer 2

Hey!!

Let

a=10cm

b=24cm

c=26cm

s= (a+b+c)÷2 =(10+24+26)÷2

=60÷2=30

Area of triangle =

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{30(30 - 10)(30 - 24)(30 - 26)}$

$\sqrt{30 \times 20 \times 6 \times 4}$

$\sqrt{2 \times 5 \times 3 \times 2 \times 2\times 5 \times 2 \times 3 \times 2 \times 2}$

$5 \times 2 \times 2 \times 2 \times 3$

$120 {cm}^{2}$

ï hope it helps u ..

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