Question

1. Find the area of Rhombus, the length of whose diagonals are 36cm
and 22.5cm.
2.The area rhombus is 148.8cm . If one of its diagonal is 19.2 cm. Find the length of the other diagonal.
3.One side of a parallelogram is 14cm. Its distance from the opposite
side is 16.5 cm. Find the area of the parallelogram.
4.The base of the parallelogram is twice its height. If the area of the
parallelogram is 512cm, find the base and the height.

Answer 1

Step-by-step explanation:

1. Area of rhombus= 1/2*36*22.5=405cm^2

2.Area of rhombus=1÷2×d1×d2

d2=148.8×2÷19.2

=148.8×2÷19.2

1448×2÷192×10÷10

1448×2÷192

=15.5

Therefore the length of other diagonal is 15.5cm

3.Area of parallelogram ⇒bh

Given b=14cm

h=16.5cm

Area ⇒bh=14×16.5

=231cm^2

4.Area of a triangle= base× height

Let us take height to be 'x' then, base will be '2x'

Since area= 512cm

512= (x)(2x)

(2x)^2=512

x^2=512/2=256

Therefore 'x' = 16

and base= '2x'= 2×16

= 32

HOPE THIS HELP !!