Question

1. Find the area of the hexagon ABCDEF Fig. (i) in which AC = 8 cm, CD = 4 cm, BM = 3 cm, NE = 10.2 cm,
DO = 5 cm, AF = 8.4 cm, OP = 3.2 cm.
P​

Answer 1

A᭄nswer:-

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REF.image

□ONCD is a square

∴NC=CD=OD=ON=5cm

AC= 8 cm

AC= AN+NC

8= AN+5

∴AN=3cm

A(ΔABC)=

2

1

×AC×BM

=

2

1

×8×3=12

A(□ONCD)=(side)

2

=5

2

=25

NE=NO+OP+PE

10.2+5+3.2+PE

∴PE=2

A(□ANPF) = length × breadth (∵□ANPF is a rectangle)

=AF×AN ∴(AN=PF)(AF=NP)

=8.4×3

=25.2

A(ΔODE)=

2

1

×(OD×DE)

=

2

1

×5×(OP+PE)

=

2

1

×5×(3.2+2)=

2

1

×5×5.2

=8

A(ΔFPE)=

2

1

×FP×PE

=

2

1

×3×2=3

∴ Area of hexagon ABCDEF=A(ΔABC)+A(ΔFPE)+A(ΔOPE)+A(□ONCD)+A(□ANPF)

=12+3+8+25+25.2

=73.2cm

2

Answer verified by Salmon bro.