Math, asked by MadGamer12, 11 months ago

1. Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM LAC, DNIAC
3cm
N 22cm
M
3cm
D

Answers

Answered by Anonymous
17

Answer:

66 cm²

Step-by-step explanation:

Area of quadrilateral = ar (∆ ABD ) + ar (∆ ADC )  

= 1/2 * AC * BM + 1/2 * AC * DAN

= 1/2 * 22 * 3 + 1/2 * 22 * 3  

=. 11 * 3 + 11 * 3

= 33 + 33

= 66

∴ Area of a quadrilateral ABCD = 66 cm² .

Answered by Anonymous
3

Answer:

66cm^2

Step-by-step explanation:

To find the area of quadrilateral ABCD, first we have to find the area of ΔABC, and ΔADC Area of ΔABC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Area of ΔADC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Then,

Area of quadrilateral ABCD = Area of ΔABC + Area of ΔADC

= 33 + 33

= 66 cm2

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