1. Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM LAC, DNIAC
3cm
N 22cm
M
3cm
D
Answers
Answered by
17
Answer:
66 cm²
Step-by-step explanation:
Area of quadrilateral = ar (∆ ABD ) + ar (∆ ADC )
= 1/2 * AC * BM + 1/2 * AC * DAN
= 1/2 * 22 * 3 + 1/2 * 22 * 3
=. 11 * 3 + 11 * 3
= 33 + 33
= 66
∴ Area of a quadrilateral ABCD = 66 cm² .
Answered by
3
Answer:
66cm^2
Step-by-step explanation:
To find the area of quadrilateral ABCD, first we have to find the area of ΔABC, and ΔADC Area of ΔABC = ½ × Base × Height
= ½ × 22 × 3
= 1 × 11 × 3
= 33 cm2
Area of ΔADC = ½ × Base × Height
= ½ × 22 × 3
= 1 × 11 × 3
= 33 cm2
Then,
Area of quadrilateral ABCD = Area of ΔABC + Area of ΔADC
= 33 + 33
= 66 cm2
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