Question

1. Find the area of the rectangle whose length=15 cm and breadth = 4.7 cm
2. Find the area of the square whose length of a side = 13.6m
3. Find the missing dimension of the rectangles whose
a) Area = 588 sq.cm & Breadth = 21 cm
b) Area = 384 sq.cm & length = 32 cm
4. Find the perimeter of the rectangle whose Area = 2925 sq.cm breadth = 45 cm

Answer 1

Answer:

1.70.5 sq.cm

2.184.96 sq.m

3.a)28cm(length)

b)12cm(breadth)

4.220cm

Step-by-step explanation:

1. Length of rectangle= 15cm

Breadth of rectangle= 4.7cm

Area of rectangle= length × breadth

$lenght \: \times breadth \\ 15 \times 4.7 \\ = {70.5cm}^{2}$

2.Side of square= 13.6m

Area of square= side × side

$side \: \times \: side \\ 13.6 \times 13.6 \\ = {184.96}m^{2}$

3.(a) Area= 588 cm.sq

Breadth= 21 cm

Length= Area/Breadth

$area \div breadth \\ \frac{588}{21} \\ = 28cm$

(b) Area= 384cm.sq

Length= 32cm

Breadth= Area/Length

$area \: \div \: length \\ \frac{384}{32} \\ = {12cm}$

4.Area of rectangle= 2925cm.sq

Breadth= 45cm

Perimeter=

[To find perimeter we should even know the length]

Lenght= Area/Breadth

$area \: \div \: breadth \\ \frac{2925}{45} \\ = 65cm$

Perimeter= 2(lenght + breadth)

$2(lenght \: + \: breadth) \\ 2(65 + 45) \\ 2(110) \\ = 220cm$