Question

(1) Find the area of the sector of a circle with radius 4 cm and the angle at the centre is 45°
(it = 3.14) [B.S.E.H. 2017 (Set-)]
th
montre is 300​

Answer 1

Answer:

the equation of any curve through the points of intersection of the circles (1) and (2) will be

(x

2

+y

2

+13x−3y)+k(2x

2

+2y

2

+4x−7y−25)=0

It is given that equation of circles passes through the point (1,1)

So,

x=1 and y=1

Substitute these value in an above equation, we get

(1+1+13−3)+k(2+2+4−7−25)=0

12−24k=0

k=

2

1

Now, Subsitute the value of k in an first equation, we get

(x

2

+y

2

+13x−3y)+

2

1

(2x

2

+2y

2

+4x−7y−25)=0

2x

2

+2y

2

+15x−

2

13y

−

2

25

=0

4x

2

+4y

2

+30x−13y−25=0