Question

1. Find the area of the shaded figure * please give me the answer fast

Answer 1

Given : ABC is a right angled triangle in which base and height of the triangle is given.

To Find : Area of the triangle.

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Here, ∆ABC is right angled at B. AB is given as 10cm which is height of the triangle and BC is given as 8cm which is base of the triangle.

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As we know that :

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$\star \: \underline{\boxed{\sf\pink{Area_{(triangle)} = \frac{1}{2} \times b \times h }}} \:$

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Where, b denotes breadth of the triangle and h denotes height of a triangle.

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$\sf:\implies \: Area_{(triangle)} = \dfrac{1}{2} \times b \times h \\ \\ \\ \sf:\implies \: Area_{(triangle)} = \frac{1}{2} \times 10 \times 8 \\ \\ \\ \sf:\implies \: Area_{(triangle)} = \cancel\frac{80}{2} \\ \\ \\ \sf:\implies \: \underline{\boxed{\mathfrak\purple{ Area_{(triangle)} = 40 \: {cm}^{2}}}} \: \bigstar \: \\ \\ \\ \\ \sf \therefore{ \underline{Hence ,\: the \: area \: of \: the \: triangle \: is \: \bold{40 \: {cm}^{2}}. }}$

Answer 2

Given:

• ∆ABC is an right angled triangle.

• AB = 10 m and BC = 8 m

To find:

• The area of the triangle.

Solution:

» A (∆) = ½ × h × b

» A (∆) = ½ × 10 × 8

» A (∆) = 40 m²

Therefore, the area of shaded region is 40 m².